What is the value of the y-intercept? I don't have a graphing calculator& studying for 2nd SAT.?

Question

1. y=x^2+8x+1

2. Y=-2x^2-8x+6

Answer 1

If you want the y intercepts, set x to 0 and solve for y.
We get
y = 1 and y = 6, respectively.

Answer 2

The y intercept by definisition is the y value when x = 0.
Simply set x = 0

1. y = 0^2 +8(0) +1
y = 1 is the intercept

2. y =-2(0^2) -8(0) +6
y = 6

Answer 3

The y-intercept is the value of y when x=0.

In #1, if x=0, y=0^2+8*0+1. So y=1.

In #2, if x=0, y=-2*0^2-8*0+6. So y=6.

Both equations are quadratics of the form y=ax^2+bx+c. Their y-ints are c.

Answer 4

oh, come on, that is easy!!! we study it in our 1st high school, which is american 9th grade..
ok hear how it goes: resolve this: x^2+8x+1=0, and draw coordinate system. when u resolve that i gave u, u will find values of graph that is on x coordinate (x1, x2). so then u see the coeficient infront of the x^2 and if it is > 0 than the parabole goes like a smiley.. ok, i don't know to explain, but ill draw the first problem:
http://img126.imageshack.us/img126/3629/untitledtq0.jpg

in the end put x=0 and ull find y intercept - y=1

Answer 5

You get the y-intercept when x=0. So put 0 into each equation to get y and that is your y-intercept.
1. (0,1)
2. (0, 6)

Here's something else you may notice when you compare the y-intercepts to the functions. The function are in y=ax^2+bx+c form.
The y-intercept is always c. (0,c)