Probability of 3 cards of each suit out of 12 cards?

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Probability of 3 cards of each suit out of 12 cards?

What is the probability of dealing 3 cards of each suit (3 spades, 3 hearts, 3 diamonds, 3 clubs) out of a 12 card hand?

2007-04-15 05:53:49 · 2 answers · asked by sassyc 1 in Science & Mathematics ➔ Mathematics

2 answers

Probability = C(13,4)^4 / C(52,12) ≈ 0.032418863

2007-04-15 15:24:15 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋

3/12 * 2/11 * 1/10 = 6/1320 = 1/220
For the first three.

3/9 * 2/8 * 1/7 = 6/504
For the second three.

etc

So multiply them together:

6^4 / 12! = 1 / 369600

2007-04-15 13:07:07 · answer #2 · answered by Anonymous · 0⤊ 1⤋