graphing g(y)?

Question

How would just graph something that's g(y) = -y^2 + 4
I know that g(x) is just a function but i have no clue what to do with this thing

Answer 1

This thing is also just a function. Are you confused because it is a y instead of an x? If so, the symbol used for the independent variable is completely arbitrary. The graph of g(x)=-x^2+4 will look the exact same as g(y)=-y^2+4 will look the exact same as g(banana)=-(banana)^2+4

Answer 2

well what you CAN do, i'm not sure if this is quite correct, but if you set -y^2 +4 = x, then solve for x, you will have half of the function. Once you graph the fcn of x, you can just use the fact that quadratic functions with the degree of 2 are symmetrical.

so, to help you out. you'd start with x = -y^2 + 4
solving for x youd get

sqrt(4 - x) = y. To get the whole picture, just stick a +/- sign in front of the sqrt and you're good to go.

Once graphed, this will look like a sideways parabola.

Answer 3

make a table : Pick values of G(y) and solve for y

g(y) -y^2 +4
-2 sqrt(6)
-1 sqrt(5)
0 sqrt (4)
1 sqrt(3)
2 sqrt(2)
3 sqrt(1)
4 0
5 imaginary

now label one axis g(y) and the other y and you can plot the points up to the point where the function becomes imaginary
Since the square roots will yield a negative and a positive value, the plot will be two curves asymtotic to negative infininty, one above the axis and one below th axis and the two curves will meet at g(y) = 4 beyond which the function is undefined

Answer 4

I have seen functions listed as f(t), g(s), etc. so if it is indeed a function, you should graph it the same way, with y here on the horizontal axis. Just be sure to label the axes correctly [horizontal y, vertical g(y)]

Answer 5

g is a function of y...

Graph the parabola that is moved 4 units up, inverted (opens down).. and label the horizontal axis y and the vertical g(y)

Answer 6

y, g(y)
y, x

1, 5
2, 8
3, 13
4, 20
5, 29
6, 40
7,