How do you solve this? Square root of the 4th root of the 5th root of x?

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thx!

2007-04-15 03:28:46 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

this is the same as X^(1/2*1/4*1/5)= x^(1^40)

This is the same as the 40th root of x or x^1/40.

2007-04-15 03:34:41 · answer #1 · answered by The exclamation mark 6 · 0⤊ 0⤋

Write it down:

n-th root of x = x^(1/n)
(a^b)^c = a^(b*c)

So it is

((x^(1/5))^(1/4))^(1/2) = x^(1/(5*4*2)) = x^(1/40)

The 40th root of x.

2007-04-15 10:34:25 · answer #2 · answered by roman_king1 4 · 0⤊ 0⤋

[[(x)^(1/5)]^(1/4)]^(1/2)] = x^(1/40)

2007-04-15 10:48:10 · answer #3 · answered by Como 7 · 0⤊ 0⤋

x^(1/5)

(x^(1/5))^(1/4)

((x^(1/5))^(1/4))^(1/2)

=> x^(1/40)

2007-04-15 11:32:18 · answer #4 · answered by Aruna R 2 · 0⤊ 0⤋