If we have two circles A and B overlapping inside a big square, and we have to shade anything's that not A and intersects with B, what should I shade?
Choice A- The circle B, minus where it overlaps with A. Choice B-Circle B, plus where it overlaps with circle A.
Choice C- circle B< minus the overlapping plus the whole square.
Or choice D- circle B, plus the overlapping, plus the whole square.
2007-04-15 02:16:43 · 5 answers · asked by Avatar Unknown 2 in Science & Mathematics ➔ Mathematics
A
it must be in B (intersects with B) and it must not be in A
2007-04-15 02:27:31 · answer #1 · answered by hustolemyname 6 · 0⤊ 0⤋
If I read the question correctly, anything that's not A excludes everything in circle 'A' including where it intersects with 'B'. But if what is to be shaded must also ('and') intersect with 'B', then there's nothing left except the part of 'B' that doesn't overlap with 'A' since 'B' is a proper subset of the universal set, (the big square) and as such everything within it intersects with the universal set.
I'd say answer A was the correct one.
HTH
Doug
2007-04-15 09:30:05 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
Choice A
2007-04-15 09:21:01 · answer #3 · answered by David K 3 · 0⤊ 0⤋
choice A
2007-04-15 09:26:02 · answer #4 · answered by shawn michaels pwns cena 4 · 0⤊ 0⤋
All the answers are right
Ana
2007-04-15 15:11:38 · answer #5 · answered by MathTutor 6 · 0⤊ 0⤋