bromoethane 2?

Question

I found 2 experiments for the reaction I need but I’m not sure which 1 is right, so could some1 please say which one is the better answer thank you................................1!!


1.

CH3CH2Br + NaOH (C2H5OH) -> CH3CH2OH + NaBr

The effect of the SodiumHydroxide(dissolved in ethanol) on the OHˉ now behaves as a base, a proton acceptor. The CH3CH2Br behaves differently from an alkane, as it is a polar molecule as it contains + C-Br ˉ as bromine is more electronegative than carbon. So because of the inductive effect (pull of the electron cloud towards the positive charge) the H’s become + as well – an elimination reaction.

NaBr + AgNOз -> AgBr + NaNOз

This will form a cream precipitate




2.
CH3CH2Br + H20 ->+ H + + Brˉ
Silver ions (from the AgNO3) the react with the Brˉ ions giving a precipitate of silver bromide
Ag+(aq) + Brˉ (aq) -> AgBr(s) this precipitate will turn cream

Answer 1

They are both right, but the second one, with just water, will be incredibly slow. They are both hydrolysis reactions, and therefore are classified as nucleophilic substitution.
The function of the silver nitrate is to check how fast the Br- ions are being produced.