Describe what would you see if you added a piece of zinc metal into 6M HCl acid?

Question

what about a piece of copper metal into 6M HCl acid?

In a separate experiment, concentrated nitric acid is added to a test tube containing a piece of copper metal.

Describe what you would see. explain differences between the results obtained in this experiment and the one from the copper metal in HCl.

Answer 1

When Zn is added to 6M HCl then the reaction is fast and a bit violent since the concentration of HCl is more.
Zn + 2HCl ---------> ZnCl2 + H2
The mixture turns hot as the reaction is exothermic.
There would however be no reaction of Copper(Cu) with HCl as in reactivity series Cu is less reactive than H.
Copper however would react with HNO3(NITRIC ACID) since HN03 except for being an acid is also a very powerfull oxidizing ahent. Thus Cu will be oxidised to Copper Nitrate.
3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O
You can see a brown gas which is NO2 from:
2NO + O2---->2NO2
The reaction here is very hot.

Answer 2

H2SO4 + Zn = Zn SO4 + H2 This equation is already balanced see: LHS: H - 2 S - 1 O - 4 Zn - 1 RHS: Zn - 1 S - 1 O - 4 H - 2

Answer 3

Zn + 2HCl -> ZnCl2 + H2

Cu + HCl -> No reaction

Cu + 2HNO3 -> Cu(NO3)2 + H2

The reason is the reduction potentials of Cu and Zn.

Answer 4

2Zn + 2HCl --> 2ZnCl + H2 (g)

Cu + HCl --> Cu+HCl no reaction takes place, because H is more reactive than Cu

Cu +2HNO3 --> Cu(NO3)2 + H2 (g)

diffrence: Cu does not react with HCl but it does react with HNO3 to produce hydrogen gas

Answer 5

Hydrogen bubbles