How much heat is released when 8.5 g of CS2 abd 8.4 of Cl2 are mixed and react according to the following...?

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CS2(g)+3Cl2(g)-->S2Cl2(g)CCl4(g) delta H=-230 KJ/mol

2007-04-14 20:50:21 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

Molar mass of CS2 = 12+64 = 76 g

8.5/76 = 0.112

8.4/71 = 0.118

Cl2 is the limiting reagent.

Thus, heat = 0.118*(-230)/3 = 9.05 kJ

2007-04-14 21:07:40 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋

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2007-04-14 21:14:34 · answer #2 · answered by Me + Me = BANG! 2 · 0⤊ 0⤋