6/(x-1) from negative infinity to 0
a. -12 b. -6 c. Divergent d. 6
2007-04-14 20:47:51 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
c.Divergent.
The integral is equal to 6*ln|x- 1| from negative infinity to 0.
In negative infinity it will be infinity and in zero it will be zero. So the result will be negative infinity, this means that answer c is correct
2007-04-14 21:08:10 · answer #1 · answered by Anonymous · 1⤊ 0⤋
The integral is 6 ln I x-1I +C which at -infinity => -infinity.
So the integral diverges
2007-04-15 11:09:23 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
6.S(x=-infinity to 0) 1/(x-1) dx = 6[ln Ix-1I](-inf to 0)
well obviously divergent
2007-04-15 04:14:35 · answer #3 · answered by yasiru89 6 · 0⤊ 0⤋
proud boys must be proud enough to do their problems themselves!
2007-04-15 09:05:37 · answer #4 · answered by Anonymous · 0⤊ 0⤋