A 20.6 g sample of metal was heated to 62.81 degrees C. When the metal was placed in a constant pressure...?

Question

calorimeter containing 30 g of water, the temp rose form 23.76 degrees C to 29.38 degrees C. Calculate the specific heat of the metal

Answer 1

Q=C*M*dt

Q=energy
C= specific heat capacity
M=mass
dt=change in temperature

Answer 2

warmth, Q, flows from warm to chilly. be confident to specify this, in any different case the verify in the suitable answer would desire to be valuable or adverse. Waters Values T_0 = 24.6 C T_f = 28.9 C m = 80.0g C_p = 4.184 J/g*C Equation to apply: Q = m * C_p * dT Q = m * C_p * (T_f - T_0) fixing the equation: Q = (80.0 g) * (4.184 J/g*C) * (28.9 C - 24.6 C) Q =1439.296 J Q = a million.40 4 kJ Notes a million.) in case you elect sig figs, i'm no longer toying with that sh1t, so which you would be able to determine that out. 2.) considering that I defined water because of the fact the gadget, and the steel because of the fact our surroundings, then the gadget valuable properties warmth, which ability the respond could be valuable. IF warmth substitute into lost, then the respond could be adverse. 3.) do no longer concern with regard to the steel, this is in simple terms there to throw you off. The question would desire to be extra complicated in case you had to throw in area transformations. in case you had to rigidity with regard to the steel, they might probably help you already know if there substitute into an element substitute or no longer. 4.) Likewise you may desire to set Q_water = Q_metal if there substitute into extra recommendations given on the steel. this style you may desire to resolve for the C_p of steel (in the event that they gave you the mass, yet no longer the C_p). you additionally can resolve for the mass of the steel (in the event that they gave you C_p, yet no longer the mass).

Answer 3

30*1*(29.38-23.76) = 20.6*c*(62.81-29.38)

Answer 4

hard one mate