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y=(4x^2+x+75)/(x^3+25x)

2007-04-14 20:28:26 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

y = 4x/(x^2 + 25) + 1/(x^2+25) +75/(x^3+25x)

y' = (4*(x^2+25) + 4x*2x)/(x^2 + 25)^2 + 2x/(x^2+25)^2 +

+ 75*(3x^2 + 25)/(x^3+25x)^2 =

= 2(6x^2+x+50)/(x^2+25)^2 + 75*(3x^2+25)/(x^3+25x)^2 =

= (2x^2(6x^2 + x +50) + 75(3x^2 + 25))/(x^3+25x)^2 =

= (12x^4 + 2x^3 +100x^2 +225x^2 + 1875)/(x^3+25x)^2

= (12x^4+2x^3+325x^2+1875)/(x(x^2+25))^2

2007-04-14 20:49:38 · answer #1 · answered by blighmaster 3 · 0 0

Definite or indefinite ???????

2007-04-15 03:36:22 · answer #2 · answered by ag_iitkgp 7 · 0 0

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