Four: 1,3,5 and 7.
How did you get 11 integers? Even if you count all the integers that can properly divide 11, the count comes to only 8.
1,3,5,7,15,21,35,105.
2007-04-14 20:04:12
·
answer #1
·
answered by jimmy20013 2
·
1⤊
1⤋
The answer is certainly not 11. It is either 4 (the integers 1, 3, 5, and 7) or 0.
Usually, "divides evenly" means "divides a whole number of times", but if the question setter is being a smart Alec he maybe expects you to realise that he is using it to mean "divides a whole even number of times". Then the answer is 0, because the numbers 1, 3, 5 and 7 do not "divide evenly" into 105, they "divide oddly" into it.
2007-04-15 10:28:02
·
answer #2
·
answered by bh8153 7
·
0⤊
0⤋
I believe four integers between 1 and 14 can divide evenly into 105: 1, 3, 5, and 7.
2007-04-15 02:39:05
·
answer #3
·
answered by Terran 3
·
2⤊
0⤋
There are 4 integers which divide evenly into 105 between 1-14 and they are 1,3,5,and 7
2007-04-15 04:32:05
·
answer #4
·
answered by Dave aka Spider Monkey 7
·
1⤊
0⤋
105 = 3*5*7
so, we have the factors 1,3,5,7 (that is it)
2007-04-15 02:41:22
·
answer #5
·
answered by MathMark 3
·
1⤊
0⤋