Find the axis of symmetry. Y = X^2 + X + 1
2007-04-14 18:56:33 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Y = ax^2 + bx + c
in this equation:
a = 1
b = 1
c = 1
axis of symmetry: x = (-b)/(2a)
x = -1/2
2007-04-14 19:02:21 · answer #1 · answered by coconutty beanz xD 4 · 0⤊ 0⤋
axis of symmetry will pass through turning point and will be vertical.for a quadratic the x-coordinate of turning point is -b/2a
Comparing X^2 + X + 1 to ax^2+bx+c
a=1
b=1
c=1
Therefor axis of symmetry is x= -1/(2x1)
x= - 0.5
2007-04-14 19:17:09 · answer #2 · answered by MasTerMinDraJ 2 · 0⤊ 0⤋
x = -b/(2a) = -1/2 is the axis of symmetry
2007-04-14 19:03:11 · answer #3 · answered by sahsjing 7 · 0⤊ 0⤋
y = x² + x + 1
y = (x² + x +1/4) - 1/4 + 1
y = (x + 1/2)² + 3/4
y = [(x - (-1/2)]² + 3/4
Axis of symmetry is x = 1/2
2007-04-15 03:59:29 · answer #4 · answered by Como 7 · 0⤊ 0⤋