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polydentate ligands result in more stable complex ions
then do monodentate ligands



An example of formation equilibrium for a complex ion in solution is:

Al3+ + 6F− ↔ [AlF6]3− Kf = 5.0 × 10−3



ΔG = −RT ln( Kf )



remember, the more negative the value the of ΔG the more stable
are the products of reaction that are formed




Which of the following are true statements ?



a) en stands for ethylenediamine, a bidentate ligand


b) The subscript f in Kf stands for 'free energy'


c) A very large value of Kf for a chemical reaction in which a coordination complex
is a product would indicate that the complex formed is a relatively stable one


d) A very large value of Kf for a chemical reaction in which a coordination complex
is a product would indicate a relatively small decrease in Gibbs free energy

2007-04-14 18:52:26 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

Yes, A and C

2007-04-16 10:37:05 · answer #1 · answered by Tommy 2 · 0 0

a) True

b) False

c) True

d) False.

2007-04-14 20:31:10 · answer #2 · answered by ag_iitkgp 7 · 1 0

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2016-11-24 19:30:07 · answer #3 · answered by gordillo 4 · 0 0

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