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if f(x) = integral 1 to 2x 1/1-t^3 dt, then f ' (x)=

2007-04-14 18:48:56 · 2 answers · asked by BP 1 in Science & Mathematics Mathematics

2 answers

f'(x) = 2x'/[1-(2x)^3] = 2/(1-8x^3)

2007-04-14 19:05:40 · answer #1 · answered by sahsjing 7 · 0 0

f¨(x)= 2/[1-(2x)^3] = 2/(1-8x^3) but not from 1 to 2x because at
1 the integral diverges.You cant inlclude 1 into the interval

2007-04-15 11:50:10 · answer #2 · answered by santmann2002 7 · 0 0

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