how do you solve this?
2007-04-14 18:02:51 · 11 answers · asked by I'm B O R E D 2 in Science & Mathematics ➔ Mathematics
3*3*3*3*3*9*9*9
3*3*3*3*3=243
9*9*9=729
243*729=177147
2007-04-14 18:06:35 · answer #1 · answered by Anonymous · 0⤊ 0⤋
change 9 to a 3 base (9^3 will become 3^6)
so you will have 3^5 times 3^6 so now that you have the same base you can just add up the powers
3^(5+6)= 3^11
2007-04-15 01:08:48 · answer #2 · answered by plaintooweird 1 · 0⤊ 0⤋
A=3^5 times9^3= 3^5times3^6=3^(5+6
)=3^11=11ln3=177147
A=177147
2007-04-15 03:06:49 · answer #3 · answered by Tuncay U 6 · 0⤊ 0⤋
3^5 * 9^3
=> 243 * 729
=> 177147 (using calculator)
or
3^5 * 9^3
=> 3^5 * (3^2)^3
=> 3^5 * 3^6
=> 3^(5+6) (law of indices)
=> 3^ 11
=>177147
which method u feel easy u can use it.
2007-04-15 11:55:12 · answer #4 · answered by Aruna R 2 · 0⤊ 0⤋
3^5 x 9^3=
243 x 729= 177147
2007-04-15 04:45:52 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
The usual way. Note that 9= 3x3. so we can replace 9^3 with 3^6. Now we have two multipliers with the same base. So we simply add exponents to get the answer of 3^11. Aint that thrilling?
2007-04-15 01:07:45 · answer #6 · answered by cattbarf 7 · 1⤊ 0⤋
replace 9^3 with 3^6 (since 9=3^2).. so it is 3^11..
2007-04-15 02:17:46 · answer #7 · answered by rodz 3 · 0⤊ 0⤋
3x3x3x3x3x9x9x9...177147. I think thats right its 3 to the power of 5 and 9 to the power of 3 i think its right.
2007-04-15 01:08:34 · answer #8 · answered by shybunnny69 2 · 0⤊ 0⤋
3^5 * 9^3
3^5 * (3*3)^3
3^5 * 3^6
3^11
2007-04-15 01:32:03 · answer #9 · answered by kumar_subodh1984 2 · 0⤊ 0⤋
use your calculator
3^5 = 243
9^3 = 729
243 * 729 = 177147
**********You cannot multiply the bases and add the exponenets becuase the bases are different use the method i showed you***************
2007-04-15 01:06:14 · answer #10 · answered by Brandon 3 · 0⤊ 0⤋