x [3x^2 - 24x + 48]
x [ (3x^2 -12x) - (12x + 48) ]
x [ (3x (x - 4) - 12 (x + 4) ]
But the signs in both brackets have to be the same. Help?
2007-04-14 17:32:46 · 12 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
In your second line it should be: x[(3x^2-12x)-(12x-48)].
2007-04-14 17:36:21 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
Can anyone tell me what I'm doing wrong? 48x - 24x^2 + 3x^3?
x [3x^2 - 24x + 48]
x [ (3x^2 -12x) - (12x - 48) ], <- you missed a sign here.
x [ (3x (x - 4) - 12 (x - 4) ]
3x(x-4)2
or
x [3x^2 - 24x + 48]
= 3x(x^2-8x+16)
= 3x(x-4)^2
2007-04-14 17:37:39 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋
x(3x^2 - 24x + 48)
Note that the expression inside can be simplified. The numbers are divisible by 3. Take 3 out by dividing the expression inside the parenthesis by 3
3x(x^2 - 8x + 16 )
Factot the expression inside the parenthesis. It is a perfect square)
3x( x - 4 ) (x - 4) or
3x (x-4)^2
2007-04-14 17:49:40 · answer #3 · answered by detektibgapo 5 · 0⤊ 0⤋
48x - 24x^2 + 3x^3
=x [3x^2 - 24x + 48]
=x [ (3x^2 -12x) - (12x - 48) ]
it must be minus 48 not 48
=x [ (3x (x - 4) - 12 (x -4) ]
=x(x-4) [3x-12]
=3x(x-4)(x-4)
=3x(x-4)^2
2007-04-14 17:39:52 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋
48x - 24x^2 + 3x^3?
x [3x^2 - 24x + 48]
x [ (3x^2 -12x) - (12x + 48) ] ===> you took out negative 12
x [ (3x (x - 4) - 12 (x -4) ] ====> we need negative 4
because (-4)*(-12) = positive 48
Good job!
x(3x-12)(x-4) and still take out 3
3x(x-4)(x-4)
3x (x-4)^2
:)
2007-04-14 17:38:17 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x [3x^2 - 24x + 48]
best to factor out a 3
3x [x^2 - 8x + 16]
see the perfect square?
3x(x-4)^2
silly.
2007-04-14 17:38:42 · answer #6 · answered by lastwayout 2 · 0⤊ 0⤋
You failed to distribute the - when you factored out -12 from the second group(-12 * 4 doesn't equal 48)
Also, there is another factor of both 3x and -12 that you've missed...
2007-04-14 17:36:03 · answer #7 · answered by Paul 2 · 0⤊ 0⤋
x [3x^2 - 24x + 48]
x [ (3x^2 -12x) - (12x + 48) ]
// it should be x [ (3x^2 -12x) - (12x - 48) ]
so x [ (3x (x - 4) - 12 (x - 4) ]
-> x(x-4)[3x-12]
-> 3x(x-4)(x-4)
2007-04-14 17:44:13 · answer #8 · answered by rOmI 2 · 0⤊ 0⤋
48x - 24x^2 + 3x^3 factor out 3x
3x(x^2-8x+16) x^2-8x+16 is a perfect square.
3x(x-4)^2
2007-04-14 17:44:47 · answer #9 · answered by yupchagee 7 · 0⤊ 0⤋
When you pulled out the -12 from line two to three, you forgot to switch the sign from 48 to -4
2007-04-14 17:36:29 · answer #10 · answered by Supermatt100 4 · 0⤊ 0⤋