how can i put this parabola in its correct equation y=8x^2?

Question

i need to know hotw to put it in this form
4p(y-k)=(x-h)^2

Answer 1

y=8x^2
(1/8)y=x^2
4(1/32)y=x^2
4(1/32)(y-0)=x^2
4(1/32)(y-0)=(x-0)^2

p = 1/32
k = 0
h = 0

Answer 2

(1/8)y =x^2

h = 0
k=0
4p= 1 / 8

p = 1 / 32


anyway why do you want to put it in that form

it is already in a good form with vertex at the origin and opening upwards and focus at (0,1/32)