70 sextillion.
This is an estimate, evidently...
2007-04-14 15:10:31
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answer #1
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answered by Vincent G 7
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The universe itself could be infinite. However, the portion of the universe that is visible to us is finite (14 billion light-years in radius).
Our galaxy has somewhere around 400 thousand million stars (400,000,000,000). Our Local Group (Milky Way, Andromeda, Triangulum + twenty-some smaller galaxies) could have up to 4 times the number of stars:
1.6 million million stars.
(long count = billion; short count = trillion).
The Local Group has a density Omega = 1 (our neighbourhood is 'flat'). It has a radius of 1 Mpc (1 Mega parsec = 3.08 million light-years). So the volume of the Local Group represents roughly 1/100,000,000,000 of the entire visible Universe. (3.1 million light-years over 14,000 million light-years, cubed)
The entire (visible) universe seems to have a density of 0.3 (or less) of Omega (it is hyperbolic). if it is as high as 0.3, then it has at least :
1.6 x 10^12 stars (number of stars in Local Group)
times
10^11 (volume of Universe over volume of Local Group)
times
0.3 (density of Universe over density of Local Group)
=
5 x 10^22
(This is a rough estimate, determined as shown above)
(Your milleage may vary)
50,000,000,000,000,000,000,000 stars
Using short count, this is 50 sextillion.
(At that scale, this is the same answer as already reported by braxton_paul -- what is a few sextillion stars among friends)
Using long count, this is
50 trilliard (or 50 thousand trillion)
2007-04-14 15:39:29
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answer #3
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answered by Raymond 7
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A research group has found that the approximate number of stars in the known universe is 70-sextillion.
2007-04-14 15:08:53
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answer #4
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answered by Chug-a-Lug 7
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I was actually going to say 5 but someone beat me to it.
I do know there is a bunch of them. And some of them are clear over there.
2007-04-14 15:20:39
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answer #5
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answered by Anonymous
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