2007-04-14 14:45:25 · 8 answers · asked by andrew 3 in Science & Mathematics ➔ Mathematics
Factor the expression.... 6x^2 + 17x + 12
First: multiply the 1st & 3rd term to get 72. find two numbers that give you 72 when multiplied & 17 (2nd term) when added/subtracted. the numbers are (8 & 9).
Sec: rewrite the expression with the new middle terms.
6x^2 + 8x + 9x + 12
Third: with 4 terms - group "like" terms & factor both sets of parenthesis.
(6x^2 + 8x) + (9x + 12)
2x(3x + 4) + 3(3x + 4)
= (3x + 4)(2x + 3)
P.S. you don't the "x" variable because, the problem is not an equation.
2007-04-14 15:51:58 · answer #1 · answered by ♪♥Annie♥♪ 6 · 3⤊ 1⤋
(3x+4)(2x+3) = 6x^2 + 17x + 12
2007-04-14 14:50:44 · answer #2 · answered by odonata 2 · 0⤊ 1⤋
look for two numbers that multiply to 72 and add to 17
9 and 8
6x^2 + 9x + 8x + 12
factor by groups
(6x^2 + 9x) + (8x + 12)
3x(2x + 3) + 4(2x + 3)
(3x + 4) (2x + 3)
2007-04-14 14:54:57 · answer #3 · answered by 7 · 0⤊ 0⤋
(3x+4)(2x+3)
3x+4=0 OR 2x+3=0
x=-4/3 OR -3/2
2007-04-14 14:52:25 · answer #4 · answered by ken_dicey 2 · 0⤊ 1⤋
It is (3x+4)(2x+3)
2007-04-14 14:52:54 · answer #5 · answered by steiner1745 7 · 0⤊ 1⤋
(2x+3)(3x+4)
2007-04-14 14:50:45 · answer #6 · answered by bz2hcy 3 · 0⤊ 1⤋
A math question...
2007-04-14 14:53:58 · answer #7 · answered by Anonymous · 0⤊ 1⤋
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2007-04-14 14:48:50 · answer #8 · answered by rpoker 6 · 0⤊ 2⤋