Probability question, number can be between 0000 and 9999, it's a lottery. I just need to know how to do this, not the answer. :)
2007-04-14 13:06:32 · 5 answers · asked by FoxBarking 3 in Science & Mathematics ➔ Mathematics
Now I feel like a dope, thanks guys.
2007-04-14 13:12:44 · update #1
I was way overthinking it.. maybe that means it is time for a break.
2007-04-14 13:13:58 · update #2
The basic formula is:
[number of times you enter] / [number of different possibilities]
To calculate the number of possibilities, take the maximum number, subtract the minimum number, and add 1.
2007-04-14 13:11:13 · answer #1 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
There are 10,000 possible numbers, and just one of them is correct. So the probability is going to be 1 out of 10,000.
You can also calculate the probability because there are 10 possible numbers for each of the four digits.
1/10 chance the first one is matching.
1/10 chance the second one matches, ....
1/10 * 1/10 * 1/10 * 1/10 = ____________
2007-04-14 20:11:42 · answer #2 · answered by ecolink 7 · 0⤊ 0⤋
There's a 1/10000 chance to get any of those numbers, so good luck!!! Just pick one!! There's no mathematical secret that says some number is more likely to be randomly selected...
2007-04-14 20:10:50 · answer #3 · answered by Anthony T 3 · 0⤊ 0⤋
Maybe I'm missing something here, but it would seem to me the probability is one in 10,000.
2007-04-14 20:10:23 · answer #4 · answered by Anonymous · 0⤊ 0⤋
independant events.
multiply the probability of each number matching correctly.
Prob(1st # right)*Prob(2nd # right)*Prob(3rd # right)*Prob(4th # right)=
10*10*10*10
2007-04-14 20:12:10 · answer #5 · answered by Anonymous · 0⤊ 0⤋