What is the theoretical yield of NO2 ? I.E., how many grams of NO2 should be formed?

Question

Nitric oxide, NO, reacts instantly with oxygen gas to give nitrogen dioxide, NO2, a dark brown gas.
In one experiment 16.81 g of NO is mixed with 10.55 g of O2.


What is the theoretical yield of NO2 ? I.E., how many grams of NO2 should be formed?

Answer 1

Molar mass of NO = 14+16 = 30 g

Moles of NO = 0.56

Moles of O2 = 10.55/32 = 0.33

NO + 1/2 O2 -> NO2

NO is the limiting reagent, thus 0.56 mol of NO2 will be formed

grams of NO2 = 46*0.56 = 25.76 g

Answer 2

replace from mass to moles. The NO is your limiting reactant. so the style of moles of NO wouldthen equivalent the style of moles of NO2. From equation 2NO +O2 <--> 2NO2 its one to a minimum of one with appreciate to the limiting reactant so it would yeild an equivalent style of moles of product. so which you will yield approximately 40.4 grams NO2 and function approximately 3.5 grams O2 left over