Write the equation of each line shown described in the following:?

Question

having a slope of 7 and containing the point (0,-4)

having a slope of -8 and containing the point (-7,2)

parallel to the line y=-4x+6 and containing the point (0,3)

perpendicular to the line y=8 through the point (2,3)

Answer 1

Slope Intercept Form

y = mx + b

- 4 = 7(0) = b

- 4 = 0 + b

- 4 = b
-- - - - -

y = 7x - 4

- - - - - -

y = mx + b

2 = - 8(- 7) + b

2 = 56 + b

2 - 56 = 56 + b - 56

- 54 = b

y = - 8x - 54

- - - - - -s-

Answer 2

The line equation is y = mx + b

(a) Having a slope of 7 and containing the point (0, -4)
m = 7
x = 0
y = -4
-4 = 7(0) + b
b = -4

y = 7x - 4

(b). Having a slope of -8 and containing the point (-7, 2).
m = -8
x = -7
y = 2

2 = -8(-7) + b
2 = 56 + b
b = -54
y = -8x - 54

(c). Parallel to the line y = -4x+6 and containing the point (0,3)
Parallel to the above line, means that the slope is the same: So m = -4
3 = -4(0) + b
3 = b
y = -4x + 3

(d). Perpendicular to the line y=8 through the point (2,3)
A line that's perpendicular to y = 8 would be a fully vertical line. Since it passes (2, 3), it would be the line x = 2.

Answer 3

1) slope = 7, x intercept = (0,-4)
y+4 = 7(x)
y = 7x - 4

2) slope = -8 and has point(-7,2)
using y-y1 = m(x-x1)

y -2 = -8(x+7)
y - 2 = -8x - 56
y = -8x - 54

3) two lines that are parallel have the same slope.
y = -4x + 6, slope = 4

line paralell containing (0,3) =
y-3 = -4(x)
y = -4x + 3

4) if perpendicular line has a slope equal to the negative reciprocal of the slope of the other line. so if the slope of one line is 2, the slope of the perpendicualr line is -1/2

y = 8
perpendicular line is x = 2

Answer 4

having a slope of 7 and containing the point (0,-4): y=7x-4

having a slope of -8 and containing the point (-7,2): Y= -8x - 56

parallel to the line y=-4x+6 and containing the point (0,3): y=4x+3

perpendicular to the line y=8 through the point (2,3): x=2

Answer 5

1)
y = 7x+c
set x=0, y=-4 from the contained point, -4 = c so c=-4.
So y = 7x -4

2)
y = -8x+c
set x=-7, y=2; 2=56 + c; c = -54
So y = -8x -54

3)
They're parallel, so the slope is the same, the offset is to be found
y = -4x +c
Set x=0, y=3; c=3
So y = -4x +3

4)
y=8 is a horizontal line.
so a perpendicular one is vertical so the line is x=c
It goes through (2,3) so x must always be 2.
x = 2

Answer 6

1). 7x-4=y
2.) -8(-7)+b=2 56+b=2 b=-54 Answer -8x-54=y
3.) -4x + 3 =y
4.) Its been awhile , but I think perpendicular slope is negative inverse . y cannot = 8 at (2,3) y=3

Answer 7

Slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept 1.) 2x + y = 7 (subtract 2x from both sides) y = -2x + 7 <===Slope: -2, y-intercept: 7 2.) 5y - 10x = 20 (add 10x to both sides) 5y = 10x + 20 (divide both sides by 5) y = 2x + 4 <===Slope: 2, y-intercept: 4 3.) -3x - y = 11 (add 3x to both sides) -y = 3x + 11 (multiply or divide both sides by -1) y = -3x - 11 <===Slope: -3, y-intercept: -11 4.) -3y = 6x - 3 y = -2x + 1 <===Slope: -2, y-intercept: 1 5.) y = (-4/5)x + 3 6.) y = (1/4)x + 2 B.

Answer 8

1. y = 7x - 4
2. y = -8x - 54
3. y = -4x - 3

i'm not sure about the 4th one thou... will get back to you when i find out... and if you still don't have the answer to it...

hope that helps! =)

Answer 9

1)Point-slope formula:
y-y1=m(x-x1)
y+4=7(x-0)
y+4=7x
y=7x-4

2)y-y1=m(x-x1)
y-2=-8(x+7)
y-2=-8x-56
y=-8x-54

3)Slope=-4
y-3=-4(x-0)
y-3=-4x
y=-4x+3

4)x=2