182 = 1* 144 + 3*12+2
so 132
2007-04-14 07:03:43
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answer #1
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answered by hustolemyname 6
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There are two basic methods for converting between bases, which I call big-endian and little-endian (computer science majors will understand why). They produce the same results, but in opposite directions.
Big-endian method:
First, find the largest power of the base which is less than or equal to your number. In this case, your base is 12, and the largest power of 12 which is less than 182 is 12², or 144. So your result will be a three-digit number (in general, if your base is b and the largest power of the base which is less than or equal to your number is b^n, you will obtain an n+1 digit number). To find the first digit, divide your number by the nth power of the base -- the integer part of that division is then your first digit. On each subsequent step, divide the remainder of the division from the last step by the next lower power of the base. Continue in this fashion until you divide by b^0 (which is 1), at which point you will have the last digit of your number.
Using this method on your example of 182:
182 ÷ 144 = 1 R 38
38 ÷ 12 = 3 R 2
2 ÷ 1 = 2
So 182 is 132 in duodecimal.
Little-endian method:
This method starts by finding the least significant digit of a number. It has the advantage that you don't have to handle powers of the base, so it's easier to implement algorithmically. It works like this:
#1: take your number, and divide it by the base. The _remainder_ of the division is the last digit of your number.
#2: to find the "next" digit of the number (which is the one just to the left of the previously found digit), take the quotient of your last division, and divide it by the base. The remainder of the division is then the next digit.
#3: repeat step 2 until your quotient is zero. Then you have found all the digits of the number.
Using this method on 182:
182 ÷ 12 = 15 R 2
15 ÷ 12 = 1 R 3
1 ÷ 12 = 0 R 1
so 182 is 132 in duodecimal.
2007-04-14 07:17:26
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answer #2
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answered by Pascal 7
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It would be 132 That means 1*12^2 +3*12^1 +2*12^0
Take the succesives remainders by dividing the number into 12 and the last quotient,starting with this
182/12=15/12=1
R=2 R=3 Last quotient =1
2007-04-14 07:12:30
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answer #3
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answered by santmann2002 7
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182 = 15*12 + 2
15 = 1*12 + 3
The answer is 132.
Check: 1*12² + 3*12 + 2 = 144 + 36 + 2 = 182.
The secret is to divide your original number by
12 until you get a quotient less than 12,
putting down the remainder each time.
Since 12 is bigger than 10, we use A for a remainder
of 10 and B for a remainder of 11.
2007-04-14 07:07:13
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answer #4
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answered by steiner1745 7
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in base 10 you have the ones column, the tens column and the hundreds column so on.
in base 12, you have the ones column, the 12's column and the 144 column.
so 182 in base 12 = .
how many 144's in 182? answer = 1, so 1 goes in the 144 column. how much is left over = 182 - 144 = 38.
so now we go to the 12's column. how many 12's in 38? answer is 3. how much is left over? 38 - 36 = 2
so 182 in base 12 is 132 which means (1 * 144) + (3 * 12) + (2 * 1) = 182
your answer is 132 base 12
2007-04-14 07:06:24
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answer #5
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answered by Anonymous
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