find the slope of a line containing the points (-4,7) and (3,-6)?

Answer 1

Slope formula

m = y₂- y₁/ x₂- x₁

m = - 6 - 7 / 3 - (- 4)

m = 13 / 3 + 4

m = 13 / 7

- - - - - - - -s-

Answer 2

Find the slope of a line containing the points (-4,7) & (3,-6)

*The slope formula is....
m = [second y - first y]/[second x - first x]

First: place the set of points in the formula.

m = [- 6 - 7]/[3 - (- 4)]

m = [-13]/[3+4]

m = -13/7

Answer 3

The slope (or gradient) of a line can be defined as the change in y divided by the change in x.

With the points you give this would be:

(7--6)/(-4-3)=13/-7=-1.86 (to 2 decimal places)

Be careful with all those negative signs - I think I got it right!

Answer 4

Slope formula:
m=(y2-y1)/(x2-x1)
m=(-6-7)/(3+4)
m=-13/7

Answer 5

The Slope Formula is:

M = y2 - y1 / x2 - x1

So substitite (y2 = -6, y1 = 7, x2 = 3, x1 = -4)

M = (-6 - 7) / (3 - -4)

M = -13 / 7

M = approximately - 1.86 or - 1 6/7

Answer 6

-4 - 3 / 7 - - 6

-7 / 13

Make a point at one of your coordinates, go 7 units to the right and 13 units down to create your line.

Answer 7

The slope of a line is equal to the change in y / change in x:

so in this case... we have (y2-y1)/(x2-x1):

(-6-7)/(3-(-4)) = -13/7 = -13/7

Answer 8

to find gradient, it's:
(Y1-Y2)/(X1-X2)

for your question:
X1=-4, Y1=7
X2=3, Y2=-6

so using the formula:
[7-(-6)]/[(-4)-3]
13/(-7)
-1.857 (approx to 4 sig. fig)

so the slope of the line containing the two points is -1.857.

hope that helps!

Answer 9

-13/7

Answer 10

-13 over 7 (change in y over change in x)

that means 13 down and 7 to the right or 13 up and 7 to the left