I have one AP Physics Free-Response Question.Can you jst give me answer or guide me though this question?

Question

While Exploring a sunken ocean liner, the principal resercher found the absolute pressure on the robot observation submarine at the level of the ship to be about 413 atmoshpere. The density of seawater is 1025 kg/m^3.
(a)How do i find gauge pressure on the sunken ocean liner

(b)Calculate the depth of the sunken ocean liner.

(c)Calculate the magnitude F of the force due to water on a viewing part of the submarine at the this depth if the viewing port has surface area of 0.0100m^2.

Suppose that ocan liner came to rest at the surface of the ocean before at started to sink .due to resistance of sea water,the sinking ocean liner then reached a terminal velocity 10.0m/s after falling 30.0 second.

(d)Find the acceleration of ocean liner during this period of time.

(e)Assume that Acceleration was constant, find the distance below the surface at which ocean liner riched the terminal velocity.

(f)find t it took the ocean liner to sink from surface to the bottom of ocean.

Answer 1

a. I sure wouldn't use a barometer. Somewhere you did the pressure gage stuff.
b. Since 1 atm = 34 feet of water, the level would be 413 x 34 feet. For metric enthusiasts, divide by 3.3 or so to get meters.
c. F= PxA. Somewhere, atmospheres converts to so many newton/m^2. Convert your 413 atm and multiply by your area.
d. For constant accleration, v = a x t.
So 10 m/sec = a x 30 sec.
a = 0.33 m/sec^2
e. For constant accleration with 0 initial velocity
d = (a/2)(t^2)
d= 0.167x 900= 150 meters
f. Take your answer for b and subtract 150 meters from it (see previous calc). Divide that distance by 10 m/sec to cover the constant velocity segment. Then add 30 seconds to cover the initial seqment.