English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

the directions go as follows:
perform the following operations and then simplify.
---2----------2
2x + 3x----x - 3x + 21----x+7
______-_________-_____
------------2
----------x - 2x - 63

that is 2x squared + 3x - x squared + 3x + 21 - x-7
over
x squared - 2x - 63

2007-04-14 04:56:42 · 7 answers · asked by mykd4sound 2 in Science & Mathematics Mathematics

that is the problem, x equals x. and I am sorry, I do not kow how to write problems that way on this site, it moves things around so yes bingo bet and mr p. have it correct as far as the problem goes, but the answer is (x-2)/(x-9), that is the asnwer in the back of the book, but I want to know how they got that answer. thank you

2007-04-14 06:00:38 · update #1

7 answers

The answer simplyfied is...

(x+2)(x+7) / (x+9) (x-7)

Just simplify the numerator and factor the numerator and the denominator.

2007-04-14 05:06:32 · answer #1 · answered by clevelandbrownsgirl2007 3 · 0 0

(2x² + 3x - x² - 3x + 21 - x - 7) / (x² - 2x - 63) =

(x² - x + 14) / (x² - 2x - 63) =

{(x + ½(1 - i√55))(x + ½(1 + i√55))} / {(x + 2 - i√62)(x + 2 + i√62)}

2007-04-14 05:11:36 · answer #2 · answered by ........ 5 · 0 0

A=a million/2bh start up via multiplying a million/2's reciprocal (opposite=2, turn the numbers) then divide each little thing via 2: 2A=bh (the a million/2 is canceled) to detect b divide each little thing via h and you get: 2A/h=b

2016-12-20 14:41:06 · answer #3 · answered by ? 3 · 0 0

didyou mean ((2x^2 + 3x) - (x^2 -3x + 21) - (x - 7))/(x^2 - 2x - 63)

2007-04-14 05:36:18 · answer #4 · answered by bingobet 3 · 0 0

geez i have a hard time reading this please update it

pls use ( ) and ^

anyway do you mean

(2x^2+(3x-x)^2+21-x-7)/(x^2-2x-63)

2007-04-14 05:04:32 · answer #5 · answered by Verident 2 · 0 0

nope

2007-04-14 04:59:49 · answer #6 · answered by Anonymous · 0 0

What is X?

2007-04-14 05:00:42 · answer #7 · answered by Andrew B 1 · 0 0

fedest.com, questions and answers