What is the equilibrium concentration of NO in this reaction: N2(g) + O2(g) 2NO(g)?

Question

Considering, the equilibrium constant for the reaction below is 0.49, and at equilibrium, [O2] = 0.11 and [N2] = 0.15.

Answer 1

[NO]^2/[N2][O2] = .49

or [NO] = sqrt(.49*.11*.15) = 8.99 x 10^-2