Solve. 5(x – 5) + 8x = 9x – 25?

5x-25+8x=9x-25
13x-25=9x-25
25-25=13x-9x
0=4x
x=0/4
x=0

2007-04-13 17:48:37 · answer #1 · answered by pokemon maniac 6 · 0⤊ 0⤋

5(x – 5) + 8x = 9x – 25
distribute five
5x - 25 +8x = 9x - 25
add 5x+8x
13x -25 = 9x -25
Subtract 9x from both sides
4x -25 = -25
add 25 to both sides
4x = 0
divide both sides by 4
x=0

TO CHECK THE SOLUTION PLUG 0 IN FOR X
5(x – 5) + 8x = 9x – 25
5(0 – 5) + 8(0) = 9(0) – 25
0-5 = -5 and 8 times 0 = 0
so
-25 = 9(0)-25
9 times 0 also equals 0
so
-25 = -25

Since your left side matches up w/ the right side
Your answer is therefore correct and you may do the happy Dance =))

2007-04-13 17:54:44 · answer #2 · answered by Alyssa 2 · 0⤊ 0⤋

Quadratic equation is : [-b ± √(b² - 4ac)] / 2a Anything with square roots that can't be factored I'll just be leaving as is. 1. 3x² - 0x - 12 = 0 [ 0 ± √(0² - 4(3)(-12))] / 2(3) [0 ± √(0 + 144)] / 6 ± √(144)] / 6 ±12/ 6 ±2 2. 4x² + 9x + 5 = 0 [-b ± √(b² - 4ac)] / 2a [-9 ± √(9² - 4(4)(5))] / 2(4) [-9 ± √(81 - 80)] / 8 [-9 ± √1]8 [-9 ± 1] / 8 Either -1 or -(5/4) 3. 5x² - 6x - 4 = 0 [6 ± √((-6)² - 4(5)(-4))] / 2(5) [6 ± √(36 + 80] / 10 [6 ± √(116)] / 10 [6 ± (√2 * √2 * √29)] / 10 [6 ± 2√29] / 10 [3 ± √29] / 5 4. -x² + x + 1 [-1 ± √(1² - 4(-1)(1))] / 2(-1) [-1 ± √(1 + 4)] / -2 [-1 ± √5] / -2 5. 2x² + 5x + 0 [-5 ± √(5² - 4(2)(0))] / 2(2) [-5 ± √(25 - 0)] / 4 [-5 ± √25] / 4 [-5 ± 5] / 4 Either 0 or -(5/2) Hopefully my calculations are all correct! 19 - Caucasian (American).

2016-05-19 21:26:29 · answer #3 · answered by mina 3 · 0⤊ 0⤋

5(x – 5) + 8x = 9x – 25

subtract 8x for both sides
5(x-5) = x - 25

distribute
5x - 25 = x - 25

add 25
5x = x

subtract x
4x = 0

divide 4
x = 0

2007-04-13 17:52:14 · answer #4 · answered by 7 · 0⤊ 0⤋

5(x – 5) + 8x = 9x – 25

First, distribute the 5:

5x – 25 + 8x = 9x – 25

Now combine like terms:

13x - 25 = 9x - 25

Now isolate the variable, subtract 9x from the right and add 25 to the right:

4x = 0

It should be pretty clear now, but divide both sides by 4 and you get:

x = 0

2007-04-13 17:49:15 · answer #5 · answered by Derrick_k 2 · 0⤊ 0⤋

open up the backets
5x - 25 + 8x = 9x - 25

simplify,
13x - 25 = 9x - 25

next, you move x to one side
13x - 9x = -25 + 25

simplify,
4x = 0

answer: x = 0

2007-04-13 17:49:26 · answer #6 · answered by Kris L 1 · 0⤊ 0⤋

5x - 25 +8x = 9x -25
5x-25+25 +8x = 9x-25+25

5x +8x = 9x
13x = 9x
-9x -9x

4x = 0
x = 0

2007-04-13 17:53:40 · answer #7 · answered by jayjay 2 · 0⤊ 0⤋

5x - 25 + 8x = 9x - 25
5x - 25 + 25 + 8x = 9x - 25 + 25
5x + 8x = 9x
13x = 9x

x has to equal 0.

Are you sure that you entered the problem correctly?

2007-04-13 17:49:25 · answer #8 · answered by TychaBrahe 7 · 0⤊ 0⤋

5(x – 5) + 8x = 9x – 25
5x - 25+ 8x = 9x -25
5x+8x-9x=-25+25
4x=0
x=0/4
x=0.

2007-04-13 18:22:25 · answer #9 · answered by Anonymous · 0⤊ 0⤋

5(x – 5) + 8x = 9x – 25
5x-25+8x=9x-25
5x+8x-9x= -25+25
4x=0

x=0

2007-04-13 18:42:54 · answer #10 · answered by R.S. ŞмЇГЭў 2 · 0⤊ 0⤋

5(x – 5) + 8x = 9x – 25
5x - 25 + 8x = 9x -25
5x + 8x - 25 = 9x -25
13x - 25 = 9x -25
-9x +25 -9x+25
_________________
4x + 0 = 0 + 0
4x = 0
x = 0

2007-04-13 17:49:33 · answer #11 · answered by Jimmy 2 · 0⤊ 0⤋

Solve. 5(x – 5) + 8x = 9x – 25?

15 answers