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4 answers

The domain of x will always be greater than 0. The reason is because you can not take the logarithm of any negative number or 0. The logarithm of 0 or a negative number does not exist. F(X) is undefined as x approaches 0.

2007-04-13 14:48:40 · answer #1 · answered by Whatever 7 · 0 0

f(x) = log base 2 x^2 =log (base e)x^2/log(base e)2 now you notice that during what circumstances this functionality fee will return actual area i.e log x^2 isn't defined at x=0 so the area is x=(-infinity,0) union (0,infinity)

2016-12-20 14:18:14 · answer #2 · answered by ? 4 · 0 0

The domain is x>0
The range is +infinity to - infnity

2007-04-13 14:46:51 · answer #3 · answered by santmann2002 7 · 0 0

domain is (0,oo)

its just 3 + ln(x)/ln(0.5)

2007-04-13 14:43:18 · answer #4 · answered by hustolemyname 6 · 0 0

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