√45x^2
This is the same as
√9 * 5 * x^2
3√5x^2
Since the x is squared, you can take the square root of it, which is just x.
3x√5
√45x^3
√9 * 5 * x^2 * x
3x√5x
√9 * 10 * x^2 * y^2 * y
3xy√10y
Get it? IM me if you need a more detailed description.
2007-04-13 12:48:14
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answer #1
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answered by its_victoria08 6
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If you factor the 45 and the 90, that will be a good start. In the first one, 45 = 3x3x5, so you can take a 3 and an x out. The answer would be /5 times 3x.
In the second one, there would be one x still under the root sign, so it would be /5x times 3x.
In the third one, 90 factors to 2x3x3x5. You can take a 3 out, an x, and a y. There's still one y under the root sign. So the answer would be /10y times 3xy.
My "/" is a root sign. Hope that helps.
2007-04-13 12:56:18
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answer #2
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answered by TitoBob 7
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√(45x²) = 3|x|√5
√x² = |x|, not x, since √(-3)² = √9 = 3 <> -3
√(45x^3) = 3|x|√(5x)
√(90x²y^3) = 3|xy|√(10y)
2007-04-13 12:51:12
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answer #3
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answered by Philo 7
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√(45x²)
√(9*5x²)
±3x√5
√(45x^3)
√(9 * 5 * x² * x)
±3x√(5x)
√(90x²y^3)
√(9 * 10 * x² * y² * y)
±3xy√(10y)
2007-04-13 12:58:14
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answer #4
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answered by Brenmore 5
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The first has the square factor 9x^2 inside the radical. take that square root and you have 3x*sqrt(5)
The second has the exact same square factor, but this time you're left with 5x inside. 3x*sqrt(5x)
The third and last has the square factor 9x^2y^2 so take that out as 3xy and you have 3xy*sqrt(10y)
2007-04-13 12:49:28
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answer #5
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answered by MLBfreek35 5
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First one = 45x
2007-04-13 12:48:06
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answer #6
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answered by Anonymous
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3x sqrtof 5
3x sqrt of 5x
3xy sqrt of 10y
2007-04-13 12:52:11
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answer #7
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answered by Dave aka Spider Monkey 7
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the square root of a number is that number times itself
2007-04-13 12:47:55
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answer #8
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answered by 1rxrech 2
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3xsqrt(5)
3xsqrt(5x)
3xysqrt(y)
2007-04-13 12:46:44
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answer #9
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answered by bruinfan 7
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