Please graph the following: 4x + y >=4?

Question

Can you please explain the way you graphed this problem?

Answer 1

4x + y ≥ 4

x = 0

y intercept

4(0) + y ≥ 4

0 + y ≥ 4

y ≥ 4

(0, 4)

- - - - - - -

y = 0

x intercept

4x + y ≥ 4

4x + 0 ≥ 4

4x ≥ 4

4x / 4 ≥ 4 / 4

x ≥ 4/4

x ≥ 1

(1, 0)

- - - - - - -s-

Answer 2

I like to graph things by putting them into slope intercept form. That is, y=mx+b

4x+y>=4
y>=-4x+y

Now you would start at positive 4 on the y axis, which is the y intercept, then make a dot there. Go down four units and one to the right (Or up four units and one to the left) and make another dot. Repeat until you have a few dots. Draw a solid line, because the solution of the inequality includes the boundary (Because of the equals sign). Finally, we are searching for all the y coordinates that are greater than, or bigger than the x. So, shade in all the points with a higher y value than the line, which would be all points above the line

Answer 3

Choose 3 pairs of numbers for x and y that would make it equal 4 - this will be the boundary line. Points such as (1,0), (2, -4) and (0,4).

Since = is included in the problem draw a solid line through the points and label it with the equation 4x + y = 4. [If there had been no =, just the >, you'd have drawn a dashed line.]

Then since it also has > in it, choose the side of the line containing points that would make 4x + y be greater than 4 and shade that side. For example the point (5,5) would work so shade the side of the boundary line that (5,5) is on.

Answer 4

ok so in reality its like all different equation. 3x+4y <12 imagine of it as 3x + 4y = 12 to locate X Intercept: Plug in 0 for y. 3x + 4(0) = 12 3x + 0 = 12 x = 4 So positioned a level at (4,0) Now do a similar for the Y Intercept: Plug in 0 for X. 3(0) + 4y = 12 0 + 4y = 12 y = 3 positioned a level at (0,3) Now, draw a line to connect both factors you've. you presently have your line. yet you're not to any extent further achieved. that is an inequality. you're unique equation became 3x + 4y < 12. So now you may want to paint your graph. with the aid of the indisputable fact that's below, you color each and every thing below your line, it really is largely each and every thing below your line, because numbers are smaller as you bypass down. Do a similar for x+3y < 6. For x>0, thats only a verticle line at (0,0) with the aid of the indisputable fact that's larger than, color each and every thing better than it, it really is each and every thing to the right, because the numbers get better in the course of the right. Do a similar for y > 0, that's a horizontal line at (0,0) and color each and every thing better than the line.

Answer 5

subtract 4x for both sides

y >/ -4x + 4

start and y = 4, then go up 4, to the left 1, up 4, to the left one. Because y is greater than -4x + 4, you shade the region that is above the line.

Answer 6

First solve for y to get y>=-4x+4.
Next plot two points that are on this line: (0,4) and (1,0) and connect them to get a line; finally, shade everything above this line.

Answer 7

convert it to slope-intercept form. Now it is y>= -4x+4
so the points are (0,4) (1,0) (-1,8) (2,-4) (-2, 12)
Draw a line through them, and then shade in the upper partition.

Answer 8

it's ok.you should graph f(x)=y=4-4x normally.then in the figure.the domain which y>=4-4x is what we need!