How many mL of 13.00M hydrochloric acid must be diluted with water to prepare 1.30L of a 0.640 M HCL solution?

0 ⤊

How many mL of 13.00M hydrochloric acid must be diluted with water to prepare 1.30L of a 0.640 M HCL solution?

2007-04-13 09:33:31 · 2 answers · asked by mimi 1 in Science & Mathematics ➔ Chemistry

2 answers

Use the equation C1V1=C2V2
your unknown is V1
(13.00M)*V1=(0.640M)*(1.30L)
V1=0.064L or 64 mL

2007-04-13 09:44:06 · answer #1 · answered by Anonymous · 0⤊ 0⤋

The equation you need to use is M1V1=M2V2 where M is the molarity of the initial and final solution, and V are the volumes of the two solution. Solve for V1.

2007-04-13 16:42:23 · answer #2 · answered by hcbiochem 7 · 0⤊ 0⤋