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The high spin d 4 complex [Cr(H2O)6] 2+ is labile, but the low spin d 4 complex [Cr(CN)6] 4is inert. Explain.?

2007-04-13 09:00:05 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

1 answers

The H2O molecules can be easily replaced as there is no back bonding involved unlike the CN- ions.

2007-04-13 19:26:16 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋

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