(3*4*12 inches) is a standard size of brick that has been used for many centuries!
It has relation to a pythagorian triplet, British system and ancient Indian Vedic Mathematics!
Said brick can be perfectly inscribed within a sphere of whole number diameter. What is the diameter of sphere? (differrent sizes of bricks can be completely inscribed within said sphere but 3*4*12 brick is special)
Brick size has an "end-area, volume, surface area" relations that could be easily remembered. What are they?
Vedic Mathematics sutras reveal a meticulous study of 'few selected radius'-spheres and reciprocal structures of related radius/diameter to grasp concerned 3D states. (You may state it but will not be used for rating a best answer)
All above said states you may read in a brick size!
Now I am keen to learn it from 'a best Yahoo answerer'!
Please do it!
2007-04-13 01:00:50 · 6 answers · asked by kkr 3 in Education & Reference ➔ Trivia
1. diameter 13" which is the length of the diagonal from L-top corner through the body center to the R-bottom corner of the brick
2. area relationships: 12:36:48 sq.in
(4x3=12, 12x3=36, 12x4=48)
3. volume 144 cu. in.
(12x3x4...oddly, 12 squared)
area&volume& side lengths are all related to the number twelve
2007-04-13 04:20:05 · answer #1 · answered by Anonymous · 2⤊ 0⤋
A little more than 6 inches. Since the longest side is 12 inches. So the diameter of the sphere has to be more than 12 inches to fit both the sides of the coboid. So it must be somewhere around 7 inches
2007-04-13 01:09:48 · answer #2 · answered by Ankit Kumar 3 · 0⤊ 1⤋
the diameter is 13 inches.i.e.(12^2+3^2+4^2)^1/2.
the leading diagonal of the cuboid will be the diameter of the sphere.
2007-04-13 01:25:15 · answer #3 · answered by ramya 3 · 2⤊ 0⤋
The diagonal of the short end is 5". The second leg of the right angle is 12". The square root of the sums of the squares of the 5 & 12 is 13".
I don't expect "best" answer. I'm just plugging in another correct one.
2007-04-13 19:31:19 · answer #4 · answered by h_brida 6 · 0⤊ 0⤋
The length of the diagonal will be the diameter of the sphere
so radius =1/2*Diagonal of brick
2007-04-13 01:51:54 · answer #5 · answered by surya m 1 · 1⤊ 1⤋
Ankit says 6 inches for radius. Parts of the circle will 'fall off' the edge. It is then necessary to reduce the diameter so all the circle fits on, ?no?
Maybe a circle/sphere of 1.5 inches radius?.
I am so hopeless at logic. But that is my guess
2007-04-13 01:14:13 · answer #6 · answered by thisbrit 7 · 0⤊ 1⤋