a.(x-5)(x+7)
b.(x+5)(x-7)
c.(x0-5)(x-7)
d.(x+5)(x+7)
2007-04-11 19:18:08 · 14 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Find the factored form of x^2+12x+35 or, 1x^2+12x+35
First: multiply the 1st term with the last term to get 35.
Sec: find two numbers that give you 35 when multiplied & 12 (2nd term) when added/subtracted. The numbers are 5 & 7. Rewrite the expression with the new middle terms.
x^2 + 5x+7x + 35
Third: with 4 terms, always group "like" terms & factor both sets of parenthesis.
(x^2 + 5x)+(7x + 35)
x(x+5) + 7(x+5)
(x+5)(x+7)
2007-04-11 19:26:46 · answer #1 · answered by ♪♥Annie♥♪ 6 · 1⤊ 2⤋
(x+5)(x+7)
7*5=35
7+5=12
x^2 + 12 x + 35
2007-04-12 02:21:32 · answer #2 · answered by ? 1 · 0⤊ 1⤋
Its d. if you mean x2 = x (2 is exponent) = x squared
So, to check it:
(x+5)(x+7) (multiply each item from left column with right column)
x2+7x+5x+35
x2+12x+35 you get the question. So d is correct.
2007-04-12 02:31:52 · answer #3 · answered by miya 3 · 0⤊ 1⤋
d.(x+5)(x+7)
2007-04-12 02:21:43 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 1⤋
x2+2x+35=(x+5)(x+7)
Ans =d
2007-04-12 02:27:53 · answer #5 · answered by Tubby 5 · 0⤊ 1⤋
It's "do your homework, lazy creature!" (I cannot call you a human being; that is a right that you have to earn and, so far, you're not doing too well.)
2007-04-12 02:21:29 · answer #6 · answered by mrquestion 6 · 0⤊ 3⤋
d
2007-04-12 06:08:55 · answer #7 · answered by rodz 3 · 0⤊ 1⤋
d
2007-04-12 02:23:18 · answer #8 · answered by Anonymous · 0⤊ 2⤋
d
2007-04-12 02:22:46 · answer #9 · answered by Billposter 2 · 0⤊ 2⤋
d
2007-04-12 02:20:46 · answer #10 · answered by Anonymous · 0⤊ 2⤋