a.(x-5)(x+2)
b.(x-5)(x-2)
c.(x+5)(x-2)
d.(x+5)(x+2)
2007-04-11 19:11:51 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
c. (x+5)(x-2)
I see D3 beat me to it.
Commit this to memory:
When the signs of a quadratic are + & +,
the binomial operators will be + & +.
+ - = ( + )( - ) [or ( - )( + )]
- + = ( - )( - )
- - = ( + )( - )
You seek two numbers whose product is -10 and whose sum is +3.
2007-04-11 19:16:05 · answer #1 · answered by Anonymous · 0⤊ 0⤋
C.
(x+5)(x-2)
=x2+5x-2x-10
=x2+3x-10
2007-04-12 03:35:31 · answer #2 · answered by dr 2 · 0⤊ 0⤋
Letter C. (x+5) (x+2) By using the FOIL method, you'd come up with: x2+3x-10
x * x = x2 F
x * -2 = -2x O
5 * x = 5x I
5 * (-2) = 10 L
2007-04-12 02:19:16 · answer #3 · answered by Nettie Anne 1 · 0⤊ 0⤋
C (x+5)(x-2)
x^2+5x-2x-10
x^2+3x-10
2007-04-12 02:15:54 · answer #4 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋
(x-2)(x+5)
2007-04-12 06:11:22 · answer #5 · answered by rodz 3 · 0⤊ 0⤋
c. (x+5)(x-2)
now can you please answer other questions on your own?
2007-04-12 02:26:12 · answer #6 · answered by ziktles 3 · 0⤊ 0⤋