Now it says to select all equations of lines passing though (0,9)
y = 9x + 2
y = 2x + 9
y = 6x + 9
y = 2x + 8
2007-04-11 18:08:00 · 7 answers · asked by cougarhw 1 in Science & Mathematics ➔ Mathematics
*The goal is replacing the point (0, 9) with the "x" & "y" variable, in order to find the correct equations.
1. y = 9x - 2
9 = 9(0) - 2
9 = 0 - 2
9 = - 2
False
2. y = 2x + 9
9 = 2(0) + 9
9 = 0 + 9
9 = 9
True
3. y = 6x + 9
9 = 6(0) + 9
9 = 0 + 9
9 = 9
True
4. y = 2x + 8
9 = 2(0) + 8
9 = 0 + 8
9 = 8
False
The equations that pass through (0, 9) are y = 2x+9 &
y = 6x+9
2007-04-11 18:39:43 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 1⤋
The answers are:
y = 2x + 9
y = 6x + 9
When you plug in the point (0,9), you get 9=9, which means the point is true. Or, you can say that since (0,9) means the line has a y-intercept of 9 and since in the equation of a line, y = mx + b, b is the y-intercept, those two equations must be the answer.
2007-04-12 01:16:33 · answer #2 · answered by chichow.duckie 2 · 0⤊ 0⤋
(0,9) is a point where x=0 and y=9. So take each equation, substitute x=0 and see if y=9. Hint: there is more than one equation that passes.
2007-04-12 01:12:33 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
y = mx+b, where b is the yintercept.
Yintercept is when x=0.
So the point (0,9) means y-intercept of 9
So any equation where b=9 (second and third)
You can plug in x=0 into each equation also and see if you get y=9?
2007-04-12 01:14:53 · answer #4 · answered by MathMark 3 · 0⤊ 0⤋
Simply substitute 0 for x in each equation and see if y=9
(Select equations 2 and 3)
2007-04-12 01:14:32 · answer #5 · answered by blighmaster 3 · 0⤊ 1⤋
its the middle two x=0 y=9. only the middle two make that true
2007-04-12 01:12:41 · answer #6 · answered by mnb 1 · 0⤊ 1⤋
Iam not sure about it ether
2007-04-12 01:11:42 · answer #7 · answered by freddy 5 · 0⤊ 1⤋