How do you determine the proportionality constant (k) of a chemical reaction?

Question

I'm so lost... I'm trying to study for my chem quiz so I don't fail and I don't understand this stuff at all... anyhow... this is in the context of discussing rates of chemical reactions, and assuming hypothetical experimentally determined values.

Answer 1

It is determined from experimental data.

Answer 2

Why will ought to that's without put off? reaction happens as a results of collisions between debris whose capability is on the least the activation energy. To make concerns undemanding do no longer ignore a common order reaction in an spectacular gas. the cost of the gas molecules could have a Maxwell-Boltzmann distribution (google this for extra information). look on the curve and verify a velocity comparable to a effortless activation capability. Mark this, as a vertical line, on the curve. the sphere to the right of this represents the form of debris whose power is above the activation energy. Now if the temperature will improve the curve strikes to the right (even nonetheless the entire subject below it maintains to be customary). which potential there'll in all probability be extra suitable molecules with adequate capability to react. yet in addition, as a results of fact the conventional velocity of the debris is larger the frequency of collisions will additionally be extra suitable. the two those 2 reasons will improve the cost of reaction as a results of fact the temperature will improve. So the dating between reaction value and temperature should not be plenty extra probably to be linear. ideally you will desire to do a mathematical assessment of this at different temperatures, the two applying calculus or numerically, and plot a graph of your effect. verify which you utilize the the ideal option fashions for temperature. i'm hoping think approximately obtained a pair of extra suitable hours left and likewise you shouldn't have in spite of else which you in simple terms have have been given to do previously the coursework should be surpassed in.