Does anyone know how to solve these problems x^2+16x and x^2-4x?

Question

Can you explain it to me also so I can get how to do it??

I have to determined the constant that should be added to the bionomial so that it becomes a perfect square trimonial. Then write and factor the trinomial.

Answer 1

Are you given an x value?
Or are you supposed to just reduce it?
Or are you supposed to set them equal to 0.


If you set them equal to 0, this is what you get:

x^2 + 16x = 0
x (x + 16) = 0
x = 0 ........... x + 16 = 0
.....................x = -16

So x = 0 and x = -16.


-----------------------------------
x^2 - 4x = 0
x (x - 4 ) = 0
x = 0 ........... x - 4 = 0
.....................x = 4

So x = 0 and x = 4.

.

Answer 2

Ok, you have to factor to find the answers:

For x^2+16x, there is a common factor in both parts, x so pull the x out of each part and you end up with x(x+16)

Do the same for the next one x(x-4).

That's assuming of course is what you wanted to do, you didnt provide an = sign so this as far as you can take it.

Answer 3

x^2 + 16x can be reduced to:

x(x + 16)

And then you set it equal to 0 to solve the problem:

x(x + 16) = 0

Then you separate the problem and solve it in parts:

x = 0

x + 16 = 0

x = -16

Those are the two solutions for that one.

x^2 - 4x can be reduced to:

x(x -4)

Set it equal to 0:

x(x-4) = 0

Separate and solve:

x = 0

x - 4 = 0

x = 4

Those are the two solutions for that one.

Answer 4

Are they in the same equation like this?

x^2+16x=x^2-4x

Or are you given a value for x?

Answer 5

x^2+16x =x(x+16)

x^2-4x=x(x-4)


if x^2+16x =0
then x1=0 x2=-16

if x^2-4x=0 then
x1=0 x2=4

Answer 6

Um. It's impossible to "solve" those if you don't provide us with information on what you're trying to find.

*If* you're trying to solve for "x", what do those equations equal? Each other? Zero? Something else? Are you trying to factorise those equations? Find the zeros?

Answer 7

if ^2 is an exponent, i can help.
well, actually theyre in simplest form, both of them, but if you multiplied them, it would be:
1. 16x^3
2. -4x^2

Answer 8

use a calculator, and if the problem doesn't fit BUY A NEW ONE!!!! Or just get the problem wrong. there..........

problem solved!