let A=
[-5e^(3t) -4e^(4t) ]
[-6e^(3t) 3e^(4t) ]
find det(A)
what i did was i did ad-bc and got -39e^(7t) but that's the wrong answer. I think i am having trouble remembering the simple properties of exponents. if someone could point out where i went wrong.Thanks.
2007-04-11 16:35:56 · 6 answers · asked by ♡♥EM♡♥ 4 in Science & Mathematics ➔ Mathematics
that IS the right answer -- good job!
2007-04-11 16:40:20 · answer #1 · answered by Kathleen K 7 · 0⤊ 0⤋
It seems right to me. The rule of multiplying exponents of the same base is that (a^b)(a^c) = a^(b+c). So the determinant here is:
(-5e^(3t))(3e^(4t)) - (-6e^(3t))(-4e^(4t)) =
-15e^(3t)e^(4t)) - 24e^(3t)e^(4t) =
-15e^(7t) - 24e^(7t) = -39e^(7t)
2007-04-11 16:44:02 · answer #2 · answered by Anonymous · 0⤊ 0⤋
-5e^3t * 3e^4t = -15e^7t
-6e^3t * -4e^4t = 24e^7t
-15e^7t - 24e^7t = -39e^7t
i get the same as you. to me it looks right.
2007-04-11 16:45:11 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Your answer, -39e^(7t) is correct!
Let's do it bit by bit:
ad = -15e^(3t+4t) = -15e^(7t)
bc = 24e^(7t)
ad -bc = -39e^(7t).
2007-04-11 16:43:05 · answer #4 · answered by steiner1745 7 · 0⤊ 0⤋
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2016-12-20 12:16:14 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I agree with your answer. Are you sure you copied the problem correctly?
2007-04-11 16:40:41 · answer #6 · answered by Anonymous · 0⤊ 0⤋