help please
find ∫(7x^2 - (9)/(x^7)
Use C as the arbitrary constant.
thank you
2007-04-11 16:18:44 · 3 answers · asked by Marla L. 1 in Science & Mathematics ➔ Mathematics
sorry that's actually ∫((7x^2 - (9)/(x^7))dx
thanks
2007-04-11 16:20:29 · update #1
The brackets are still unbalanced in your followup. There are two possible questions here, so I'll answer both.
∫(7x^2 - 9/x^7) dx
= ∫(7x^2 - 9x^(-7)) dx
= (7/3)x^3 - (9/(-6))x^(-6) + C
= (7/3)x^3 + 3/(2x^6) + C
∫(7x^2 - 9)/x^7 dx
= ∫(7x^(-5) - 9x^(-7)) dx
= (7/(-4))x^(-4) - (9/(-6))x^(-6) + C
= -7/(4x^4) + 3/(2x^6) + C
2007-04-11 16:25:44 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
(7/3) x^3 -(9/8) x^8 +C
simply using the power rule integral of x^n = 1/(n+1) * x^(n+1)
2007-04-11 23:22:14 · answer #2 · answered by MathMark 3 · 0⤊ 0⤋
sorry i can anwer that
2007-04-11 23:24:44 · answer #3 · answered by ofe 1 · 0⤊ 0⤋