What is the variance in the set of data below?
45, 57, 38, 46, 49, 41
2007-04-11 15:14:25 · 5 answers · asked by apromiseibroke 1 in Science & Mathematics ➔ Mathematics
first you have to find the mean... the mean is equal to 46
Then (45-46)^2+(57-46)^2+(38-46)^2+(46-46)^2+(49-46)^2+(41-46)^2 = 300
And the standard deviation is equal to 300/5=60
and the variance is 60^2=360
2007-04-11 15:17:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
First find the mean for this data: xbar
Subtract the mean from each data point. Do this for every data point. These are called deviations: x - xbar
Square each of the deviations: (x - xbar)^2
Add all of the squared deviations together.
Divide by n - 1 (in this case, 6 -1 = 5)
This will be the variance. If you need the standard deviation, simply take the square root of the variance.
hope this helps
2007-04-11 22:20:35 · answer #2 · answered by birdwoman1 4 · 0⤊ 0⤋
If you have a TI calculator do it like this: {45,57,38,46,49,41}->L1 Next push the stat button and under operations press 1-var statistics and enter L1 after words and press enter. What follows will be the mean, variance, and standard deviation--among other things.
2007-04-11 22:19:06 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋
Variance is the average of the squares of the numbers minus the square of the average of the numbers.
2007-04-11 22:18:24 · answer #4 · answered by Scott H 3 · 0⤊ 0⤋
19. The variance is the difference between the smallest and the largest number.
2007-04-11 22:19:31 · answer #5 · answered by ragin bull 1 · 0⤊ 1⤋