I am supposed to find the height (in feet) for this rocket.?

Question

I was given a formula to use: H=-16t^2 +Vt. The Inital Velocity(V) is 48 feet per second and the times(t) are as follows 0, .5, 1, 1.5, 2, 2.5, 3.

I know it seems simple as you've just got to plug in the numbers but I've run into a block and it would be very helpful to compare answers. Please help! The first few I've got for H= are as follows (Time=0, height=0) ,(time=.5, height =22), (time=1, height=32), etc. Please solve and let me know what you get for these #'s!

I also have another with the same formula but initial velocity=64 ft. per sec. and times are as follows 0, .5, 1, 1.5,2,2.5,3,3.5,4.

Thank You!

Answer 1

t = 0 and t = 1 are OK, but for t = .5, you should have a height of 20 feet.

Answer 2

t 0, .5, 1, 1.5, 2, 2.5, 3
H 0, 20, 32, 36, 32, 20 , 0
It's just a parabola where the rocket hits a max height of 36 when t = 1.5 and then falls back to the ground.

Your other equation is also a parabola but its max will occur when t= 2