ok this ones is diffrent, i think
Perpendicular? not?
3y=-2x+12, y=-3/2x-12
does the 3 in front of the y make it perpendicular??
Help!!
2007-04-11 15:07:49 · 4 answers · asked by Rachel 1 in Science & Mathematics ➔ Mathematics
No, these two lines are not perpendicular since the slopes are not negative reciprocals--just reciprocals.
2007-04-11 15:13:12 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
solve for y for both equations (second ones already solved)
3y = -2x + 12
y = (-2/3)x + 4
the number in front of the x is the slope, so we have a slope of (-2/3) and (-3/2). If two slopes are perpendicular, they should be the negative reciprical, which they arent in this case, so the two lines are not perpendicular (the slope of the second should be (3/2) to make them perpendicular
2007-04-11 15:13:50 · answer #2 · answered by Link 4 · 0⤊ 0⤋
3y=-2x+12, y=-3/2x-12
take the first equation and divide by 3 to solve for y and to find the slope.
so now you have:
y=-2/3x+4, y=-3/2x-12
in order for them to be perpendicular, their slopes have to be negative reciprocals of each other. to test if their slopes are negative reciprocals, multiply the slopes.. if they are, you should get -1. (-2/3)(-3/2)=1
no, not perpendicular.
2007-04-11 15:15:53 · answer #3 · answered by abcdefghijklmnopqrstuvwxyz 1 · 0⤊ 0⤋
Yes, the equation of the line becomes y=-2/3x + 12, so the lines are perpendicular.
2007-04-11 15:11:05 · answer #4 · answered by teh_frigrator 2 · 0⤊ 1⤋