Need solution for this limit problem.
lim x->1 x/ln(x).
Thanks.
2007-04-11 14:48:04 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
As x approaches 1 from the negatives (from the left) the function approaches negative infinity.
As x approaches 1 from the positives (from the right) the function approaches positive infinity.
Since there are 2 different values this function approaches at the point x=1, the limit does not exist.
2007-04-11 14:53:45 · answer #1 · answered by BB 2 · 0⤊ 2⤋
y = x/ln x is discontinuous at x = 1
As x --> 1 from the left, y --> - infinity
As x --> 1 from the right, y --> +infinity
2007-04-11 22:01:24 · answer #2 · answered by ironduke8159 7 · 0⤊ 1⤋
wait no hospital rule has to be infinit/infinit or 0/0 so this limit is undefined
2007-04-11 21:52:12 · answer #3 · answered by w1ckeds1ck312121 3 · 1⤊ 0⤋
Plug and chug. Substitute values close to 1 and see where its heading. Try 0.8, 0.9, 0.95, 0.99, etc...
2007-04-11 21:53:22 · answer #4 · answered by Nicholas V 2 · 0⤊ 1⤋