What is the total number of solutions for equation 4x^2 - 2x = 5?

Answer 1

The total number of solutions is equal to the highest exponent.

4x^2 - 2x =5 has two solutions

x^3 + 3x^2 + 3x = 4 has 3 solutions

And so on. But the solutions may be repeated, so watch out for that.

Answer 2

One needs to get this equation in a special form and then apply a special formula to it. The special form equates the problem to zero, so:

4x^2 -2x -5 =0 (subtracted 5 from both sides)

now its in the form of Ax^2 + Bx + C =0

the solution for x is (-B +/- SQRT(B^2 -4AC))/2A

if the square root is negative, then the equation has no solutions

Answer 3

4x² - 2x - 5 = 0

discriminant = (-2)² - 4(4)(-5) = 4 + 80 = 84
since that's > 0, 2 real solutions.

Answer 4

All quadratic equations (ones having an x^2 term) have 2 solutions, although they may be duplicates or complex values.

To find the solutions, one side of the equation must equal zero. Then factor or apply the quadratic formula. Set each factor equal to zero and solve for x.

hope that helps!

Answer 5

4x^2-2x-5=0 has 2 real solutions.

x=(2+/-√(4+80))/8
x=1/4+1/4 √21
x=1/4-1/4 √21

Answer 6

2, solve with the quadratic equation.

Answer 7

2 solutions since it is quadratic.