If side RS is 8cm, RU is 32 cm, BC is 12cm, then What is the measure of BE?

Answer 1

This sounds like a similar triangles problem. If you have two triangles that are similar (i.e. corresponding angles are the same - one just looks bigger than the other), then the sides are proportional. It depends on how your triangles are laid out, but once you figure out which sides and angles are corresponding, then you can set up your proportions.

If you have triangle RSU and it is proportional to triangle BCE, then RS ~ BC, SU ~ CE, and RU ~ BE. (These relationships I've listed only work if angle R corresponds to angle B, angle S corresponds to angle C, and angle U corresponds to angle E. If not, you'd have to rewrite your relationships to match.) So if these sides are proportional, and you have some given sides, you can find the missing one:

RS/BC = RU/BE
8/12 = 32/BE
BE = 128

Answer 2

Your gonna have to give me the figure and all other givens, if possible.