Calorimetry...?

Question

If a reaction involved 10.4 moles of reactant how many kilojoules of heat were involved per mole of reactant? What I know is that delta T is 20 degrees Celsius and that after the reaction the temperature rose and that there was 2000. g of water surrounding the reaction and the specific heat of the surrounding water is 4.184 J/kg*K.

Answer 1

Simple! Convert 2,000g to kg, then it's:

2 x 4.184 x 20/10.4