physics numbre?

Question

Find center of mass of the ladder. To a good approximation, the ladder can be described as consisting of three parts with uniform mass distribution: a left leg(ab) with the mass Mab=10 kg, a right leg(bc) with the mass Mbc=15 kg and a crossbar (de) with the mass Mde=4kg. Coordinates of the points a,b,c,d and e are all given(meters). Xa=0, Ya=0, Xb=2, Yb=5, Xc=4, Yc=0, Xd=1.25, Yd=3, Xe=2.75, Ye=3. Precision of your answer should be atleast .1m

Find moment of inertia of the ladder in problem 2 about the axis perpendicular to x-y plane n going through point b.

Answer 1

X=My/mt
Y=Mx/mt


Mx=sum (yi mi) for i=1 to number of elements
My=sum (xi mi) for i=1 to number of elements

mi= sum(mi) for i=1 to number of elements

since the ladder is not symmetrical position the ladder 1 m (arbitrary ) above x axis and parallel to the x axis (arbitrary).

Also what about the rungs? The a,b,c,d,e are their positions. Crossbar waht are its attachemnt point(geometry)?

Answer 2

If the mass is distributed uniformly, the co-ordinates of the center of mass would be the mean of each coordinate if you put one corner of the ladder at x,y,z = 0,0,0.

I notice that your specifications do not indicate any z co-ordinates! If it is a ladder it should have length (x), width (y) AND DEPTH (z).
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